1-1/2-1/6-1/12-1/20-1/30=

2024-05-19 02:00

1. 1-1/2-1/6-1/12-1/20-1/30=

1-1/2-1/6-1/12-1/20-1/30
=1-(15/30-5/30-2.5/30-1.5/30-1/30)
=1-(15-5-2.5-1.5-1)/30
=1-5/30
=1-1/6
=5/6

1-1/2-1/6-1/12-1/20-1/30=

2. 1/2+1/4+1/8+1/16......+1/256=?

这是等比数列,首项a1=1/2,公比q=1/2,a8=a1*q7次方=256

1/2+1/4+1/8+1/16......+1/256
=S8
=1/2 *(1-(1/2)8次方)/(1-1/2)
=1-(1/2)8次方
=1-1/256
=255/256

3. 1/(1*4)+1/(4*7)+1/(7*10)+1/(10*13)+1/(13*16)+1/(16*19)+1/(19*22)=?

楼主你好,此题初见可知,分母的表现形式为乘积且存在等差关系,分子为1,求几个数字之和
1.我们当然不应该硬算,题目有一定规律,从等差入手,把题目视为求数列之和,找出“通项”(每个乘号左边1,4,7...求出通项3n-2,每个乘号右边4,7,10.....求出通项3n+1,)所以通项可视为1/(3n
-2)*(3n+1)
2求和,从以上通项可知1/(3n-2)*(3n+1)=[1/(3n-2)-1/(3n+1)]*1/3,然后就能把原式进行拆分,消去同项,进行简易求和,最后是(1-1/22)*1/3=7/22
楼主看在数学题难打的情况上给个采纳吧。。。不会的地方还可以追问我

1/(1*4)+1/(4*7)+1/(7*10)+1/(10*13)+1/(13*16)+1/(16*19)+1/(19*22)=?

4. 4/1+12/1+24/1+40/1+......19800/1

4/1+12/1+24/1+40/1+......19800/1
=1/2×(1/2+1/6+1/12+1/20+......+1/9900)
=1/2×(1-1/2+1/2-1/3+1/3-1/4+1/4-1/5+......+1/99-1/100)
=1/2×(1-1/100)
=1/2×99/100
=99/200

5. 5/(7/11)/(11/16)/(16/35)

5/(7/11)/(11/16)/(16/35)=5*11/7/11*16/35*16=5/7*16/35*16=16*16/49=256/49
满意请采纳

5/(7/11)/(11/16)/(16/35)

6. 3/2+13/6+37/12+81/20+151/30+253/42+393/56+577/72等于几

3/2+13/6+37/12+81/20+151/30+253/42+393/56+577/72
=(1+1/2)+(2+1/6)+(3+1/12)+..+(8+1/72)
=(1+2+3+.+8)+(1/2+1/6+..+1/72)
=(1+8)×8/2+(1-1/2+1/2-1/3+...+1/8-1/9)
=36+1-1/9
=36有8/9
明教为您解答,
如果能帮助到您,希望您点击(满意回答)
如果不能请追问,我会尽全力帮您解决的~
答题不易,如果您有所不满愿意,请谅解~

7. 3*5=4²-1,5*7=6²-1,...,11*13=12²-1,...

第n个等式:
(2n+1)(2n+3)=(2n+2)²-1

3*5=4²-1,5*7=6²-1,...,11*13=12²-1,...

8. 1 2 3/2 8/3 15/6 ( )[ A 53/15 B 52/15 C 49/15 D 48/15

道题考虑久觉题目点问题应该数列
1,2,3/2
8/3
15/8
(
)
规律:1X2=2
2X3/2=3
3/2X8/3=4
8/3X15/8=5
15/8X(?)=6
……
48/15
选D
若非题目错误期待高手解答